b^2=11b-28

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Solution for b^2=11b-28 equation:


Simplifying
b2 = 11b + -28

Reorder the terms:
b2 = -28 + 11b

Solving
b2 = -28 + 11b

Solving for variable 'b'.

Reorder the terms:
28 + -11b + b2 = -28 + 11b + 28 + -11b

Reorder the terms:
28 + -11b + b2 = -28 + 28 + 11b + -11b

Combine like terms: -28 + 28 = 0
28 + -11b + b2 = 0 + 11b + -11b
28 + -11b + b2 = 11b + -11b

Combine like terms: 11b + -11b = 0
28 + -11b + b2 = 0

Factor a trinomial.
(4 + -1b)(7 + -1b) = 0

Subproblem 1

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Subproblem 2

Set the factor '(7 + -1b)' equal to zero and attempt to solve: Simplifying 7 + -1b = 0 Solving 7 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1b = 0 + -7 -1b = 0 + -7 Combine like terms: 0 + -7 = -7 -1b = -7 Divide each side by '-1'. b = 7 Simplifying b = 7

Solution

b = {4, 7}

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